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A steam engine intakes 100 g of steam at...

A steam engine intakes 100 g of steam at `100^(o)C` per minute and cools it down to `20^(o)C`. Calculate the heat rejected by the steam engine per minute. Latent heat of vaporization of steam `=540 cal g^(-1)`.

Text Solution

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Heat rejected during the condensation of steam in one minute
`=(100 g)xx(540 cal g^(-1)=5.4xx10^(-4) cal`.
Heat rejected during the cooling of water
`=(100 g)xx(1 cal g^(-1)(0)C^(-1))(100(0)C-20(0)C)`
`=8000 cal`.
Thus, heat rejected by the engine per minute
`=5.4xx10^(4) cal+0.8xx10^(4) cal`
`=6.2xx10^(4)cal`.
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