calculate the change in internal energy of a gas kept in a rigid container when 100 J of heat is supplied to it.

Answer

A

Explanation

Here, `Q=100J`
`We know,`DeltaU=DeltaQ-DeltaW
Here, since the container is rigid,`
`(DeltaV)=0`
` Hence the `DeltaW=PDeltaV=0`
`So,`DeltaU=DeltaQ=100 J.