In the given figure, the value of x is

Answer

A, C, D

Explanation

`delta Q = 2.4cal`
`delta W = _AB+W_BC+W_AC`
` = 0+(1)/(2)xx(100+200)xx10^3xx200`xx106(-6)-100xx10^3xx200xx10^(-6)`
`(1)/(2)xx300xx10^3xx200xx10^(-6)-20`
` = 30J = -20J = 10J`
`Delta U = 0(in a cycle process)`
`DeltaQ = Delta U+DeltaW`
`rArr 2.4J = (10)/2.4) = (100)/(24) = (25)/(6) = 4.17J/cal`