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A gas is taken along the path AB as shown in fig, if 70 cal of heat is extracted from the gas in the process, calculate the change in the internal energy of the system.

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The correct Answer is:
A, B, D
Delta Q = 70cal = (70xx4.2)J`
`Delta W = (1)/(2)xx(200+500)xx10^3xx150xx10^(-6)`
` = (1)/(2)xx700xx150xx10^(-3)`
` = 525xx10^(-1) = 52.5J`
`Delta U = ?`
`DeltaQ = DeltaU+Delta W`
`rArr -294 = Delta U+52.5`
`rArr Delta U = -294-52.5 = -346.5J
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