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Find the dimensional formula of epsilon0...

Find the dimensional formula of `epsilon_0` .

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`epsilon_0=Coulomb/newton m^2 `
` epsilon_0=(1)/(KF)xx(q_1q_2)/r^2=M^-1L^-3T^4`
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Knowledge Check

  • The dimensional formula for tension is

    A
    `[MLT]`
    B
    `[MLT^-1]`
    C
    `[MLT^-2]`
    D
    `[MLT^-3]`

  • The dimensional formula for area is

    A
    `[M^2L^2T^2]`
    B
    `[MLT^2]`
    C
    `[M^0L^2T^2]`
    D
    `[M^0L^2T^0]`

  • The dimensional formula for stress is

    A
    `[MLT^-2]`
    B
    `[ML^-1T^-1]`
    C
    `[ML^-1T^-2]`
    D
    `[ML^-2T^-3]`

    • Similar Questions

    Explore conceptually related problems

    The velocity of a body is given by the equation v= b//t + ct^(2) + dt^(3) . Find the dimensional formula for b.

    The dimensional formula for force is

    The dimensional formula for work is

    The dimensional formula for velocity is

    The dimensional formula for energy is

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