Two chargea `2.0xx10^(-6) C` and `1.0xx10^(-6) C` are placed at a separation of 10 cm. where should a third charge be placed such that it experiences no net force due to these charges.

Explanation

`q_1=2.0xx10^-6C `
` q_2=1.0xx10_-6C `
` r=10cm=0.1m `
` F_(1q)=(9xx10^9xx1.0xx10^-6xxq)/x^2 `
` F_(2q)=(9xx10^9xx10^-6xxq)/(10-x)^2 `
` F_(1q)-F_(2q_=0 `
` So, `
` (9xx10^9xx10^-6xxq)/x^2=(9xx10^9xx10^-6xxq)/(10-x^2) `
` x^2=2(10-x)^2 `
` x=5.9cm `
From the rarger charge to the line joining the charge in the side to the smaller charge.