Three identical charges, each having a value `1.0 xx10^(-8)C,` are placed at the corners of an equilateral triangle of side 20 cm find the electric field and potential at the centre of the triangle.

Explanation

` Q=1.0xx10^-8C, L=20cm , E=?,V=? `
Since it forms an equipotential surface So, the electric field at the centre is 0
` R=(2xx10^-1)^2-(10^-1)^2 `
` =4xx10^-2-10^-2 `
Distance of centre from each charge
` =2/3xx10^-2(4-1) `
` 2/3xx10^-1xx1.732 `
` =1.15xx10^-1 `
` V=23xx10^2=2.3xx10^3V`