An electric field of `20 N//C` exists along the x-axis in space. Calculate the potential difference `V_B - V_A` where the points A and B are given by
a. `A=(0,0), B=(4m, 2m)`
b. `A=(4m,2m),B=(6m,5m)`
c. `A= (0,0 ), B = (6m,5m).`

Explanation

` (a) A=(0,0) B=(4,2) E=20N//C `
` So, v_b-v_aE.d=20xx(0-4) `
` (b) A=(4m,2m),B=(6m,5m) `
` rArr v_b-v_a=exxd `
` =20xx(4-6)^2 `
` =20xx(-2)=-40volt. `
` (c) A=(0,0),b=(6m,5m) `
` rArr v_b-v_a=exxd `
` 20xx(0-6)^2 `
` =20xx(-6)=120volt. `
Thus potential difference between `(0,)and (4,2)is,`
` dV=-E.dx=-20xx4 `
` =-80volt. `
` Potential energy (u_b-u_a)between the ponts=dvxxq`