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Two charged particles, having equal charges of `2.0xx 10^(-5) C` each, are brought from infinity to within a separation of 10 cm. Find the increase in the electric potential energy during the process.

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` q_1-q_2 =2xx10^-5C `
Each are brought from infinity to `10cm` apart `d=10xx10^-2m`
So, work done = negative of work done
`(Potential E) `
` =9xx10^9xx(2xx10^-5xx2xx10^-5)/(10xx10^-2) `
` 36J`
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