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A wire of resistance 10Omega is bent to ...

A wire of resistance `10Omega` is bent to form a complete circle. Find its resistance between two diametrically opposite points.

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Let ABCDA be the wire of resistance 10(Omega). We have to claculate the resistance of this loop between the diametrically opposite points A and C. The wire ADC and ABC will have resistances `5(Omega)`each. These two are joined in parallel between A and C. The equivalent resistance R between A and C is therfore, given by
`R=(5(Omega)xx5(Omega))/(5(Omega)+5(Omega))=2.5(Omega).
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