A current of 10.0 nA is established in a circular loop of radius 5.0 cm. find the magnetic dipole moment of the current loop. : The magnetic dipole moment is `vec mu= veciA`.

Explanation

: The magnetic dipole moment is
`vec mu= veciA`. Thus, `mu = I pi r^2 = (10 X10^(-9)A) (3.14) xx (5X10^(-2) m)^2 .= 7.85 xx 10^(-11) Am ^2.`