Fe^+ ions are accelerated through a potential difference of 500 V and are injected normally into a homogeneous magnetic field B of strength 20.0 m T. Find the radius of the circular paths followed by the isotopes with mass numbers 57 and 58. Take the mass of an `ion = A (1.6 X10^(-27)` kg where A is the mass number.

Explanation

`V = 500 V,`
`B = 20m T = (20 xx 10^(-4)) T `
Using v^(2) = 2 nd`
Hence V_(1) = 11.sin theta xx 10^(-7) m = 119 cm`
`V_(2) = 1.20 m 120 cm`.