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Figure shows a part of an electric circu...

Figure shows a part of an electric circuit. ABCD is a rectangular loop made of uniform wire. The length AD= BC = 1 cm. The sides AB and DC are long as compared to the other two sides. Find the magnetic force per unit length acting on the wire DC due to the wire AB if the ammeter reads 10A.

Text Solution

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Solution: By symmetry, each of the wires AB and DC
carries a current of 5A. As the separation between them
is 1 cm, the magnetic force per unit length of DC is
` dF/dl= ((m_0)(i_1)(i_2)/(2 pi d))`
` = ( 2 xx (10^ -7) TmA^-1 (5A)(5A)/(1 xx (10^-2)m))`
` = 5 xx (10^-4) TA = 5 xx (10^-4) N (m^-1).`
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