Consider the situation of the previous problem. Define displacement resistance `(R_d = V/i_d)` of the space between the plates where V is the potential difference between the plates and `i_d` is the displacement current. Show that `R_d` varies with time as ` (R_d)= (R(e^(t/tau)-1).)

If the strength of current flows through a resistor is I having resistance R and potential difference between its ends is V then the power dissipated is:

Consider the situation of the previous problem. A particle having charge q and mass m is projected from the point Q in a direction going into the plane of the diagram. It is found to describe a circle of radius r between the two plates. Find the speed of the charged particle.

A parallel plate condenser has a uniform electric field E (V//m) in the space between the plates. If the distance between the plates is d (m) and area of each plate is A (m^2) the energy (joules) stored in the condenser is:

The charge on a parallel plate capacitor varies as q = q_(0) cos 2 pi gamma t. the plates are very large and close together. (area- A, separation -d) find the displacement current through the capacitor?

A parallel- plate capacitor having plate-area A and plate separation d is joined to a battery of emf epsilon and internal resistance R at t=0. Consider a plane surface of area A/2, parallel to the plates and situated symmetrically between them. Find the displacement current through this surface as a function of time.

A,B and C are voltmetres of resistance R, 1.5R and 3R as shown in the figure. When some potential difference is applied between X and Y the voltmetre readings are V_A , V_B and V_C respectively , Then: