The selling rate of a radioactive isotope is decided by its activity. What will be the second-hand rate of a one month old `P^32``(t_(1//2)=14.3` days) source if it was originally purchased for 800 rupees?

Answer

A

Explanation

Given `t 1/2 = 14.3` days
` t = 30 days = 1 = month `
As the selling rate is decided by the activity ,
` I, l A_(0) = 800 disintegration// sec`
` We know A = A_(0) e^(-lambda t ) `
` i.e. A = 800 xx e^(-0.693)/(14.9) xx 30 `
` = 800 xx 0.233669 `
` 186 .935 = 187 Rupees `.