The potential difference between the terminals of an electric heater is 60 V when it draws a current of 4 A from the 3 source. What current will the heater draw if the potential difference is increased to 172.5 V?

Options

A. `10 A`
B. `24 A`
C. `8.5A`
D. `11.5 A`

Answer

To solve the problem step by step, we will use Ohm's Law, which states that Voltage (V) = Current (I) × Resistance (R).

### Step 1: Identify the given values
We know:
- Initial potential difference (V1) = 60 V
- Initial current (I1) = 4 A

### Step 2: Calculate the resistance (R)
Using Ohm's Law, we can rearrange the formula to find the resistance:
\[ R = \frac{V}{I} \]

Substituting the known values:
\[ R = \frac{V1}{I1} = \frac{60 \, \text{V}}{4 \, \text{A}} = 15 \, \Omega \]

### Step 3: Identify the new potential difference (V2)
The new potential difference is given as:
- V2 = 172.5 V

### Step 4: Use the resistance to find the new current (I2)
Since the resistance remains constant, we can use the same formula:
\[ I2 = \frac{V2}{R} \]

Substituting the known values:
\[ I2 = \frac{172.5 \, \text{V}}{15 \, \Omega} \]

### Step 5: Perform the calculation
Now, we will calculate I2:
\[ I2 = \frac{172.5}{15} = 11.5 \, \text{A} \]

### Conclusion
The heater will draw a current of 11.5 A when the potential difference is increased to 172.5 V.

### Final Answer
The answer is **11.5 A**.

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