The resulting value of 0.5 div 12.5 + 0.25 xx 0.05 - 0.0125 is
Find the sum of the following series , (i) 0.5 + 0.05 + 0.005 + 0.0005+… (ii) 0.3 + 0.18 + 0.108 + …
A series is given, with one number missing. Choose the correct alternative from the given ones that will complete the series. -0.5, -0.35, -0.2, -0.05, ? , 0.25
Find: (i) 2.5 xx 0.3 (ii) 0.1 xx 51.7 (iii) 0.2 xx 316.8 (iv) 1.3 xx 3.1 (v) 0.5 xx 0.05 (vi) 11.2 xx 0.15 (vii) 1.07 xx 0.02 (viii) 10.05 xx 1.05 (ix) 101.01 xx 0.01 (x) 100.01 xx 1.1
The solubility of AB_(2) is 0.05 g per 100 mL at 25^@ C .Calculate K_(sp) of AB_(2) at 25^(@)C ? [Atomic mass of A = 20 amu, atomic mass of B = 40 amu]
