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A solid spherical metal ball of diameter...

A solid spherical metal ball of diameter 72 cm is melted and recast into small solid cones of diameter 6 cm and height 6 cm. Find the number of cones that can be formed using this melted metal.
A)3456 cones
B)3600 cones
C)3568 cones
D)3200 cones

A

3456 cones

B

3600 cones

C

3568 cones

D

3200 cones

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the number of small cones that can be formed from a melted solid spherical metal ball, we will follow these steps: ### Step 1: Calculate the volume of the spherical metal ball. The formula for the volume \( V \) of a sphere is given by: \[ V = \frac{4}{3} \pi r^3 \] where \( r \) is the radius of the sphere. Given the diameter of the sphere is 72 cm, the radius \( r \) is: \[ r = \frac{72}{2} = 36 \text{ cm} \] Now, substituting the radius into the volume formula: \[ V = \frac{4}{3} \pi (36)^3 \] Calculating \( 36^3 \): \[ 36^3 = 36 \times 36 \times 36 = 46656 \] Thus, the volume of the sphere becomes: \[ V = \frac{4}{3} \pi (46656) = \frac{186624}{3} \pi = 62208 \pi \text{ cm}^3 \] ### Step 2: Calculate the volume of one small cone. The formula for the volume \( V \) of a cone is given by: \[ V = \frac{1}{3} \pi r^2 h \] where \( r \) is the radius and \( h \) is the height of the cone. Given the diameter of the cone is 6 cm, the radius \( r \) is: \[ r = \frac{6}{2} = 3 \text{ cm} \] The height \( h \) of the cone is 6 cm. Now substituting these values into the volume formula: \[ V = \frac{1}{3} \pi (3)^2 (6) \] Calculating \( (3)^2 \): \[ (3)^2 = 9 \] Thus, the volume of the cone becomes: \[ V = \frac{1}{3} \pi (9)(6) = \frac{54}{3} \pi = 18 \pi \text{ cm}^3 \] ### Step 3: Find the number of cones that can be formed. Let \( n \) be the number of cones that can be formed. Since the volume of the melted sphere is equal to the total volume of the cones formed, we have: \[ 62208 \pi = n \times 18 \pi \] Dividing both sides by \( \pi \): \[ 62208 = n \times 18 \] Now, solving for \( n \): \[ n = \frac{62208}{18} \] Calculating \( \frac{62208}{18} \): \[ n = 3456 \] ### Conclusion The number of cones that can be formed using the melted metal is \( \boxed{3456} \).
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