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The LCM of 76 and 57 is : A)114 B)171 ...

The LCM of 76 and 57 is :
A)114
B)171
C)152
D)228

A

114

B

171

C

152

D

228

Text Solution

AI Generated Solution

The correct Answer is:
To find the Least Common Multiple (LCM) of 76 and 57, we can follow these steps: ### Step 1: Prime Factorization First, we need to perform the prime factorization of both numbers. - **For 76**: - 76 can be divided by 2 (the smallest prime number): \[ 76 \div 2 = 38 \] - 38 can also be divided by 2: \[ 38 \div 2 = 19 \] - 19 is a prime number. So, the prime factorization of 76 is: \[ 76 = 2^2 \times 19^1 \] - **For 57**: - 57 can be divided by 3 (the smallest prime number that divides it): \[ 57 \div 3 = 19 \] - 19 is a prime number. So, the prime factorization of 57 is: \[ 57 = 3^1 \times 19^1 \] ### Step 2: Identify the Highest Powers of Each Prime Factor Next, we identify the highest power of each prime factor present in both factorizations. - The prime factors we have are 2, 3, and 19. - From 76, we have: - \(2^2\) - \(19^1\) - From 57, we have: - \(3^1\) - \(19^1\) Now we take the highest power of each prime: - For 2: \(2^2\) (from 76) - For 3: \(3^1\) (from 57) - For 19: \(19^1\) (common in both) ### Step 3: Calculate the LCM Now, we multiply these highest powers together to find the LCM: \[ \text{LCM} = 2^2 \times 3^1 \times 19^1 \] Calculating this step-by-step: 1. Calculate \(2^2 = 4\) 2. Multiply by \(3\): \[ 4 \times 3 = 12 \] 3. Finally, multiply by \(19\): \[ 12 \times 19 = 228 \] ### Final Answer Thus, the LCM of 76 and 57 is: \[ \text{LCM} = 228 \] The correct option is **D) 228**. ---
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