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A tank has two inlets which can fill it ...

A tank has two inlets which can fill it in 4 hours and 6 hours, respectively. An outlet can empty the full tank in 8 hours. Both inlet taps are opened for an hour and closed. Then the three pipes are opened together. The remaining part of the tank fills in :
(a)`5(1)/(3)` hours
(b)2 hours
(c)`3(1)/(4)` hours
(d)3 hours

A

`5(1)/(3)` hours

B

2 hours

C

`3(1)/(4)` hours

D

3 hours

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the filling and emptying rates of the pipes involved. ### Step 1: Determine the rates of the inlet and outlet pipes. - **Inlet A** fills the tank in 4 hours. Therefore, its rate is: \[ \text{Rate of A} = \frac{1 \text{ tank}}{4 \text{ hours}} = \frac{1}{4} \text{ tank/hour} \] - **Inlet B** fills the tank in 6 hours. Therefore, its rate is: \[ \text{Rate of B} = \frac{1 \text{ tank}}{6 \text{ hours}} = \frac{1}{6} \text{ tank/hour} \] - **Outlet C** empties the tank in 8 hours. Therefore, its rate is: \[ \text{Rate of C} = \frac{1 \text{ tank}}{8 \text{ hours}} = \frac{1}{8} \text{ tank/hour} \] ### Step 2: Calculate the combined rate of both inlets when opened together. When both inlets A and B are opened together, their combined rate is: \[ \text{Combined rate of A and B} = \frac{1}{4} + \frac{1}{6} \] To add these fractions, we find a common denominator, which is 12: \[ \frac{1}{4} = \frac{3}{12}, \quad \frac{1}{6} = \frac{2}{12} \] Thus, \[ \text{Combined rate of A and B} = \frac{3}{12} + \frac{2}{12} = \frac{5}{12} \text{ tank/hour} \] ### Step 3: Calculate the amount filled after 1 hour with both inlets open. In 1 hour, both inlets fill: \[ \text{Amount filled in 1 hour} = \frac{5}{12} \text{ tank} \] ### Step 4: Determine the remaining part of the tank. Since the tank is full (1 tank) and we filled \(\frac{5}{12}\) of it, the remaining part is: \[ \text{Remaining part} = 1 - \frac{5}{12} = \frac{12}{12} - \frac{5}{12} = \frac{7}{12} \text{ tank} \] ### Step 5: Calculate the combined rate when all three pipes are opened. Now we will open all three pipes (A, B, and C). The combined rate is: \[ \text{Combined rate of A, B, and C} = \frac{1}{4} + \frac{1}{6} - \frac{1}{8} \] Finding a common denominator for 4, 6, and 8, which is 24: \[ \frac{1}{4} = \frac{6}{24}, \quad \frac{1}{6} = \frac{4}{24}, \quad \frac{1}{8} = \frac{3}{24} \] Thus, \[ \text{Combined rate} = \frac{6}{24} + \frac{4}{24} - \frac{3}{24} = \frac{7}{24} \text{ tank/hour} \] ### Step 6: Calculate the time to fill the remaining part of the tank. To find out how long it will take to fill the remaining \(\frac{7}{12}\) of the tank at the combined rate of \(\frac{7}{24}\) tank/hour, we set up the equation: \[ \text{Time} = \frac{\text{Remaining part}}{\text{Combined rate}} = \frac{\frac{7}{12}}{\frac{7}{24}} = \frac{7}{12} \times \frac{24}{7} = \frac{24}{12} = 2 \text{ hours} \] ### Step 7: Calculate the total time taken. The total time taken is the time both inlets were open plus the time taken to fill the remaining part: \[ \text{Total time} = 1 \text{ hour} + 2 \text{ hours} = 3 \text{ hours} \] ### Final Answer: Thus, the remaining part of the tank fills in **3 hours**, which corresponds to option (d). ---
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