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Starting from a stationary position, Sun...

Starting from a stationary position, Sunil moves his car to attain a velocity of `20ms^(-1)` in 10s. Find the acceleration of the car.

A

`2ms^(1)`

B

`2ms^(-2)`

C

`2ms^(-1)`

D

`2ms^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the acceleration of the car, we can use the formula for acceleration in terms of initial velocity, final velocity, and time. The formula is: \[ a = \frac{v - u}{t} \] Where: - \( a \) is the acceleration, - \( v \) is the final velocity, - \( u \) is the initial velocity, - \( t \) is the time taken. ### Step-by-step Solution: 1. **Identify the initial and final velocities:** - The initial velocity \( u = 0 \, \text{m/s} \) (since the car starts from a stationary position). - The final velocity \( v = 20 \, \text{m/s} \). 2. **Identify the time taken:** - The time \( t = 10 \, \text{s} \). 3. **Substitute the values into the acceleration formula:** \[ a = \frac{v - u}{t} = \frac{20 \, \text{m/s} - 0 \, \text{m/s}}{10 \, \text{s}} \] 4. **Calculate the acceleration:** \[ a = \frac{20 \, \text{m/s}}{10 \, \text{s}} = 2 \, \text{m/s}^2 \] 5. **Conclusion:** - The acceleration of the car is \( 2 \, \text{m/s}^2 \).
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Knowledge Check

  • A particle starting from rest attains a velocity of 50 ms^(-1) in 5 s. The acceleration of the particle is

    A
    `5 m/s^2`
    B
    `10 m/s^2`
    C
    `50 m/s^2`
    D
    `100 m/s^2`
  • A body of mass 2kg starts from rest and moves with uniform acceleration. It acquires a velocity 20ms^-1 in 4s . Find average power transferred to the body in first 2s .

    A
    `50W`
    B
    `100W`
    C
    `150W`
    D
    `200W`
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