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1.080 invested for 3 months gave an inte...

1.080 invested for 3 months gave an interest of 0.027. The simple rate of interest per annum was :
(a)`2.5 %`
(b)`5%`
(c)`7.5%`
(d)`10%`

A

`2.5 %`

B

`5%`

C

`7.5%`

D

`10%`

Text Solution

AI Generated Solution

The correct Answer is:
To find the simple rate of interest per annum, we can use the formula for simple interest: \[ \text{Simple Interest (SI)} = \frac{P \times R \times T}{100} \] Where: - \( P \) = Principal amount (the initial amount of money) - \( R \) = Rate of interest per annum - \( T \) = Time (in years) Given: - Principal \( P = 1.080 \) - Simple Interest \( SI = 0.027 \) - Time \( T = 3 \text{ months} = \frac{3}{12} \text{ years} = \frac{1}{4} \text{ years} \) ### Step 1: Substitute the known values into the formula We can rearrange the formula to solve for \( R \): \[ R = \frac{SI \times 100}{P \times T} \] Substituting the known values: \[ R = \frac{0.027 \times 100}{1.080 \times \frac{1}{4}} \] ### Step 2: Calculate the denominator First, calculate \( 1.080 \times \frac{1}{4} \): \[ 1.080 \times \frac{1}{4} = \frac{1.080}{4} = 0.270 \] ### Step 3: Substitute back into the equation for \( R \) Now substitute \( 0.270 \) back into the equation for \( R \): \[ R = \frac{0.027 \times 100}{0.270} \] ### Step 4: Calculate the numerator Calculate \( 0.027 \times 100 \): \[ 0.027 \times 100 = 2.7 \] ### Step 5: Calculate \( R \) Now substitute this value into the equation: \[ R = \frac{2.7}{0.270} \] Calculating this gives: \[ R = 10 \] ### Conclusion Thus, the simple rate of interest per annum is: \[ \text{Rate} = 10\% \] The correct answer is (d) 10%. ---
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