Home
Class 14
MATHS
The difference between a fraction and it...

The difference between a fraction and its reciprocal is `9/11` If the cubes of both the fraction and its reciprocal are considered, what will be the difference between them?

A

`3996/1331`

B

`1331/2538`

C

`729/1331`

D

`2538/1331`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will start with the information given and apply algebraic identities to find the required difference between the cubes of the fraction and its reciprocal. ### Step-by-Step Solution: 1. **Define the Fraction**: Let the fraction be \( x \). Then, its reciprocal is \( \frac{1}{x} \). 2. **Set Up the Equation**: According to the problem, the difference between the fraction and its reciprocal is given by: \[ x - \frac{1}{x} = \frac{9}{11} \] 3. **Cube Both Sides**: We need to find the difference between the cubes of the fraction and its reciprocal, which is \( x^3 - \frac{1}{x^3} \). We can use the identity: \[ (a - b)^3 = a^3 - b^3 - 3ab(a - b) \] Here, let \( a = x \) and \( b = \frac{1}{x} \). So, we have: \[ x - \frac{1}{x} = \frac{9}{11} \] Therefore, \[ (x - \frac{1}{x})^3 = x^3 - \frac{1}{x^3} - 3 \cdot x \cdot \frac{1}{x} \cdot (x - \frac{1}{x}) \] Simplifying gives: \[ (x - \frac{1}{x})^3 = x^3 - \frac{1}{x^3} - 3(x - \frac{1}{x}) \] 4. **Substitute the Known Value**: Substitute \( x - \frac{1}{x} = \frac{9}{11} \) into the equation: \[ \left(\frac{9}{11}\right)^3 = x^3 - \frac{1}{x^3} - 3 \cdot \frac{9}{11} \] 5. **Calculate \( \left(\frac{9}{11}\right)^3 \)**: \[ \left(\frac{9}{11}\right)^3 = \frac{729}{1331} \] 6. **Substitute and Rearrange**: Now we have: \[ \frac{729}{1331} = x^3 - \frac{1}{x^3} - \frac{27}{11} \] Convert \( \frac{27}{11} \) to have a denominator of \( 1331 \): \[ \frac{27}{11} = \frac{27 \times 121}{11 \times 121} = \frac{3267}{1331} \] 7. **Combine the Fractions**: Rearranging gives: \[ x^3 - \frac{1}{x^3} = \frac{729}{1331} + \frac{3267}{1331} \] This simplifies to: \[ x^3 - \frac{1}{x^3} = \frac{729 + 3267}{1331} = \frac{3996}{1331} \] 8. **Final Answer**: Thus, the difference between the cubes of the fraction and its reciprocal is: \[ \frac{3996}{1331} \]
Promotional Banner

Similar Questions

Explore conceptually related problems

The difference between a positive fraction and its reciprocal is 6(39)/(160) . What is the fraction under consideration ?

The difference of 16 and its reciprocals is equal to

What is the product of 5/129 and its reciprocal ?

Sum of a fraction and thrice its reciprocal is frac(31)(6). What is the fraction?

A fraction is greater than its reciprocal by (9)/(20) .What is the fraction?

A fraction is greater than twice its reciprocal by 7/15 what is the fraction

The sum of a number and its reciprocal is thrice the difference of the number and its reciprocal. The number is :