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Find the LCM of 63 and 140 ....

Find the LCM of 63 and 140 .

A

63

B

14

C

126

D

1260

Text Solution

AI Generated Solution

The correct Answer is:
To find the Least Common Multiple (LCM) of 63 and 140, we will follow these steps: ### Step 1: Prime Factorization of 63 - We start by dividing 63 by the smallest prime number, which is 3. - \( 63 \div 3 = 21 \) - Next, we divide 21 by 3 again. - \( 21 \div 3 = 7 \) - Finally, 7 is a prime number. - So, the prime factorization of 63 is: \[ 63 = 3^2 \times 7^1 \] ### Step 2: Prime Factorization of 140 - We start by dividing 140 by the smallest prime number, which is 2. - \( 140 \div 2 = 70 \) - Next, we divide 70 by 2 again. - \( 70 \div 2 = 35 \) - Now, we divide 35 by the next smallest prime number, which is 5. - \( 35 \div 5 = 7 \) - Finally, 7 is a prime number. - So, the prime factorization of 140 is: \[ 140 = 2^2 \times 5^1 \times 7^1 \] ### Step 3: Identify the Highest Powers of Each Prime - Now, we will identify the highest power of each prime factor from both factorizations: - For the prime number 2: The highest power is \( 2^2 \) (from 140). - For the prime number 3: The highest power is \( 3^2 \) (from 63). - For the prime number 5: The highest power is \( 5^1 \) (from 140). - For the prime number 7: The highest power is \( 7^1 \) (from both). ### Step 4: Calculate the LCM - We multiply the highest powers of all prime factors together to find the LCM: \[ \text{LCM} = 2^2 \times 3^2 \times 5^1 \times 7^1 \] - Calculating this step-by-step: - \( 2^2 = 4 \) - \( 3^2 = 9 \) - \( 5^1 = 5 \) - \( 7^1 = 7 \) Now, we multiply these values: \[ 4 \times 9 = 36 \] \[ 36 \times 5 = 180 \] \[ 180 \times 7 = 1260 \] ### Final Answer The LCM of 63 and 140 is: \[ \text{LCM} = 1260 \]
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