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The HCF of (2)/(3),(8)/(9),(10)/(27),(32...

The HCF of `(2)/(3),(8)/(9),(10)/(27),(32)/(81)` is:

A

`(160)/(81)`

B

`(160)/(3)`

C

`(2)/(3)`

D

`(2)/(81)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the HCF (Highest Common Factor) of the fractions \( \frac{2}{3}, \frac{8}{9}, \frac{10}{27}, \frac{32}{81} \), we can use the formula: \[ \text{HCF} = \frac{\text{HCF of numerators}}{\text{LCM of denominators}} \] ### Step 1: Identify the numerators and denominators The numerators are: 2, 8, 10, 32 The denominators are: 3, 9, 27, 81 ### Step 2: Calculate the HCF of the numerators To find the HCF of the numerators (2, 8, 10, 32): - The factors of 2: 1, 2 - The factors of 8: 1, 2, 4, 8 - The factors of 10: 1, 2, 5, 10 - The factors of 32: 1, 2, 4, 8, 16, 32 The common factors are 1 and 2. Thus, the HCF of 2, 8, 10, and 32 is **2**. ### Step 3: Calculate the LCM of the denominators To find the LCM of the denominators (3, 9, 27, 81): - The prime factorization of 3: \( 3^1 \) - The prime factorization of 9: \( 3^2 \) - The prime factorization of 27: \( 3^3 \) - The prime factorization of 81: \( 3^4 \) The LCM is found by taking the highest power of each prime factor. Here, the highest power of 3 is \( 3^4 \). Thus, the LCM of 3, 9, 27, and 81 is **81**. ### Step 4: Calculate the HCF of the fractions Now, we can substitute the HCF of the numerators and the LCM of the denominators into the formula: \[ \text{HCF} = \frac{\text{HCF of numerators}}{\text{LCM of denominators}} = \frac{2}{81} \] ### Final Answer: The HCF of the fractions \( \frac{2}{3}, \frac{8}{9}, \frac{10}{27}, \frac{32}{81} \) is \( \frac{2}{81} \). ---
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