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The LCM of 112, 72 and 90 is...

The LCM of 112, 72 and 90 is

A

7560

B

2520

C

5040

D

3780

Text Solution

AI Generated Solution

The correct Answer is:
To find the LCM (Least Common Multiple) of the numbers 112, 72, and 90, we will follow these steps: ### Step 1: Prime Factorization First, we need to find the prime factorization of each number. - **112**: - Divide by 2: \(112 \div 2 = 56\) - Divide by 2: \(56 \div 2 = 28\) - Divide by 2: \(28 \div 2 = 14\) - Divide by 2: \(14 \div 2 = 7\) - 7 is a prime number. So, the prime factorization of 112 is \(2^4 \times 7^1\). - **72**: - Divide by 2: \(72 \div 2 = 36\) - Divide by 2: \(36 \div 2 = 18\) - Divide by 2: \(18 \div 2 = 9\) - Divide by 3: \(9 \div 3 = 3\) - Divide by 3: \(3 \div 3 = 1\) So, the prime factorization of 72 is \(2^3 \times 3^2\). - **90**: - Divide by 2: \(90 \div 2 = 45\) - Divide by 3: \(45 \div 3 = 15\) - Divide by 3: \(15 \div 3 = 5\) - 5 is a prime number. So, the prime factorization of 90 is \(2^1 \times 3^2 \times 5^1\). ### Step 2: Identify the Highest Powers of Each Prime Factor Now, we will take the highest power of each prime factor from the factorizations: - For \(2\): The highest power is \(2^4\) (from 112). - For \(3\): The highest power is \(3^2\) (from both 72 and 90). - For \(5\): The highest power is \(5^1\) (from 90). - For \(7\): The highest power is \(7^1\) (from 112). ### Step 3: Calculate the LCM Now we can calculate the LCM by multiplying these highest powers together: \[ \text{LCM} = 2^4 \times 3^2 \times 5^1 \times 7^1 \] Calculating this step-by-step: 1. \(2^4 = 16\) 2. \(3^2 = 9\) 3. \(5^1 = 5\) 4. \(7^1 = 7\) Now multiply these values together: \[ \text{LCM} = 16 \times 9 \times 5 \times 7 \] Calculating it in parts: - \(16 \times 9 = 144\) - \(144 \times 5 = 720\) - \(720 \times 7 = 5040\) Thus, the LCM of 112, 72, and 90 is **5040**. ### Final Answer The LCM of 112, 72, and 90 is **5040**. ---
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