Find the least number to be added to 1739 so that it is exactly divisible by 11
A. 11
B. 2
C. 1
D. 10

Options

A. A
B. B
C. C
D. D

Answer

To find the least number to be added to 1739 so that it is exactly divisible by 11, we can follow these steps:

### Step 1: Divide 1739 by 11
We start by dividing 1739 by 11 to find the remainder.

\[ 1739 \div 11 = 158 \quad \text{(quotient)} \]
Calculating the product of the quotient and 11:
\[ 158 \times 11 = 1738 \]

### Step 2: Find the Remainder
Now, we find the remainder by subtracting the product from 1739:
\[ 1739 - 1738 = 1 \]
So, the remainder when 1739 is divided by 11 is 1.

### Step 3: Determine the Least Number to Add
To make 1739 exactly divisible by 11, we need to eliminate the remainder. Since the remainder is 1, we need to add:
\[ 11 - 1 = 10 \]
Thus, we need to add 10 to 1739 to make it divisible by 11.

### Step 4: Verify
Now, let's check if adding 10 to 1739 gives us a number that is divisible by 11:
\[ 1739 + 10 = 1749 \]
Now, divide 1749 by 11:
\[ 1749 \div 11 = 159 \quad \text{(exactly)} \]
Since there is no remainder, 1749 is divisible by 11.

### Conclusion
The least number to be added to 1739 so that it is exactly divisible by 11 is **10**.