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What will be the Highest Common Factor o...

What will be the Highest Common Factor of `2^3xx3^5xx5^5 and 3^1xx5^2xx7^1`?

A

`2^1xx3^1xx5^2`

B

`2^1xx3^1xx5^2xx7^1`

C

`2^3xx3^5xx5^7xx7^1`

D

`3^1xx5^2`

Text Solution

AI Generated Solution

The correct Answer is:
To find the Highest Common Factor (HCF) of the two numbers \(2^3 \times 3^5 \times 5^5\) and \(3^1 \times 5^2 \times 7^1\), we will follow these steps: ### Step 1: Identify the prime factors The first number can be expressed as: - \(2^3\) - \(3^5\) - \(5^5\) The second number can be expressed as: - \(3^1\) - \(5^2\) - \(7^1\) ### Step 2: List the prime factors with their powers Now, we will list the prime factors and their corresponding powers from both numbers: 1. **For \(2^3 \times 3^5 \times 5^5\)**: - \(2\) has a power of \(3\) - \(3\) has a power of \(5\) - \(5\) has a power of \(5\) 2. **For \(3^1 \times 5^2 \times 7^1\)**: - \(3\) has a power of \(1\) - \(5\) has a power of \(2\) - \(7\) has a power of \(1\) ### Step 3: Determine the common prime factors Next, we identify the common prime factors between the two numbers: - The common prime factors are \(3\) and \(5\). ### Step 4: Take the minimum power of each common prime factor Now, we take the minimum power of each common prime factor: - For \(3\): The minimum power is \(\min(5, 1) = 1\) - For \(5\): The minimum power is \(\min(5, 2) = 2\) ### Step 5: Write the HCF Now we can write the HCF using the common prime factors and their minimum powers: \[ \text{HCF} = 3^1 \times 5^2 \] ### Step 6: Calculate the HCF Calculating the HCF: \[ 3^1 = 3 \] \[ 5^2 = 25 \] \[ \text{HCF} = 3 \times 25 = 75 \] ### Final Answer Thus, the Highest Common Factor (HCF) of \(2^3 \times 3^5 \times 5^5\) and \(3^1 \times 5^2 \times 7^1\) is \(75\). ---
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