Home
Class 14
MATHS
A sum becomes 14 times of itself in 15 y...

A sum becomes 14 times of itself in 15 years at the rate of simple interest per annum. In how many years will the sum becomes 92 times of itself?

A

91 years

B

195 years

C

105 years

D

210 years

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the reasoning presented in the video transcript. ### Step 1: Understand the Problem We need to determine how many years it will take for a sum of money to become 92 times itself, given that it becomes 14 times itself in 15 years. ### Step 2: Define the Variables Let's assume the principal amount (P) is 1 unit. According to the problem: - After 15 years, the amount (A) becomes 14 times the principal. - So, A = 14P = 14 units. ### Step 3: Calculate the Interest Earned The interest earned (SI) can be calculated as: \[ \text{SI} = A - P = 14 - 1 = 13 \text{ units} \] ### Step 4: Use the Simple Interest Formula The formula for simple interest is: \[ \text{SI} = \frac{P \times R \times T}{100} \] Where: - SI = Simple Interest - P = Principal - R = Rate of interest per annum - T = Time in years From the previous steps: - SI = 13 units - P = 1 unit - T = 15 years Substituting these values into the formula: \[ 13 = \frac{1 \times R \times 15}{100} \] ### Step 5: Solve for Rate (R) Rearranging the equation to find R: \[ R = \frac{13 \times 100}{15} \] \[ R = \frac{1300}{15} = 86.67 \text{ (approximately)} \] ### Step 6: Calculate Interest for 92 Times the Principal Now we need to find out how long it will take for the amount to become 92 times the principal: - If the principal is 1 unit, then the amount will be 92 units. - The interest earned in this case will be: \[ \text{SI} = A - P = 92 - 1 = 91 \text{ units} \] ### Step 7: Use the Simple Interest Formula Again Now we will use the same formula to find the time (T) required to earn 91 units of interest: \[ 91 = \frac{1 \times R \times T}{100} \] Substituting R from Step 5: \[ 91 = \frac{86.67 \times T}{100} \] ### Step 8: Solve for Time (T) Rearranging the equation to find T: \[ T = \frac{91 \times 100}{86.67} \] \[ T = \frac{9100}{86.67} \approx 105 \text{ years} \] ### Final Answer Thus, it will take approximately **105 years** for the sum to become 92 times itself. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

A sum becomes 5 times of itself in 3 years at compound interest (interest is compounded annually). In how many years will the sum becomes 125 times of itself?

A sum becomes 8 times of itself in 7 years at the rate of compound interest (interest is compounded annually). In how many years will the sum becomes 4096 times of itself?

A sum of money becomes four times itself in 5 years at a certain rate of interest, compounded annually. In how many years will it become 16 times itself at the same rate of interest?

A sum becomes three times of itself in 10 years at the rate of simple interest. What is the rate of interest per annum?

A certain amount of sum is invested at simple interest. If the sum becomes k times itself in 16 years and 2k times itself in 40 years, in how many year will it become 4k times of itself?