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The curved surface area of a cone is 550...

The curved surface area of a cone is 550cm sq . If the area of its base is 154 cm sq , then what will be the volume of the cone?

A

`2464cm^(3)`

B

`1836cm^(3)`

C

`1232cm^(3)`

D

`1472cm^(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the volume of the cone given its curved surface area and the area of its base, we can follow these steps: ### Step 1: Understand the given information We know: - Curved Surface Area (CSA) of the cone = 550 cm² - Area of the base = 154 cm² ### Step 2: Use the formula for the curved surface area The formula for the curved surface area of a cone is given by: \[ \text{CSA} = \pi r l \] where \( r \) is the radius and \( l \) is the slant height of the cone. ### Step 3: Substitute the values into the CSA formula We can substitute the CSA value into the formula: \[ \pi r l = 550 \] Using \( \pi \approx \frac{22}{7} \): \[ \frac{22}{7} r l = 550 \] ### Step 4: Calculate the area of the base to find the radius The area of the base of the cone is given by: \[ \text{Area of base} = \pi r^2 \] Substituting the area of the base: \[ \pi r^2 = 154 \] Again using \( \pi \approx \frac{22}{7} \): \[ \frac{22}{7} r^2 = 154 \] ### Step 5: Solve for \( r^2 \) To isolate \( r^2 \): \[ r^2 = \frac{154 \times 7}{22} \] Calculating: \[ r^2 = \frac{1078}{22} = 49 \] Thus, \( r = \sqrt{49} = 7 \) cm. ### Step 6: Substitute \( r \) back to find \( l \) Now we substitute \( r \) back into the CSA formula to find \( l \): \[ \frac{22}{7} \times 7 \times l = 550 \] This simplifies to: \[ 22l = 550 \] So, \[ l = \frac{550}{22} = 25 \text{ cm} \] ### Step 7: Use the Pythagorean theorem to find the height \( h \) We know that: \[ l^2 = r^2 + h^2 \] Substituting the known values: \[ 25^2 = 7^2 + h^2 \] Calculating: \[ 625 = 49 + h^2 \] Thus, \[ h^2 = 625 - 49 = 576 \] So, \[ h = \sqrt{576} = 24 \text{ cm} \] ### Step 8: Calculate the volume of the cone The volume \( V \) of the cone is given by: \[ V = \frac{1}{3} \pi r^2 h \] Substituting the known values: \[ V = \frac{1}{3} \times \frac{22}{7} \times 7^2 \times 24 \] This simplifies to: \[ V = \frac{1}{3} \times \frac{22}{7} \times 49 \times 24 \] Calculating: \[ V = \frac{1}{3} \times 22 \times 7 \times 24 \] \[ V = \frac{1}{3} \times 3696 = 1232 \text{ cm}^3 \] ### Final Answer The volume of the cone is \( 1232 \text{ cm}^3 \). ---
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