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The area of the base of a right circular...

The area of the base of a right circular cone is ` (1408 )/(7) cm^2`and its height is 6 cm. Taking `pi = (22)/(7)`, the curved surface area of the cone is:

A

`(1670 )/(7) cm^2`

B

`(1067 )/(7) cm^2`

C

`(1760)/(7) cm^2`

D

` (7160 )/(7) cm^2`

Text Solution

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The correct Answer is:
To find the curved surface area of a right circular cone, we can follow these steps: ### Step 1: Find the radius of the base The area of the base of the cone is given by the formula: \[ \text{Area of base} = \pi r^2 \] We know that the area of the base is \(\frac{1408}{7} \, \text{cm}^2\) and \(\pi = \frac{22}{7}\). Therefore, we can set up the equation: \[ \frac{22}{7} r^2 = \frac{1408}{7} \] ### Step 2: Solve for \(r^2\) To eliminate the fraction, we can multiply both sides by 7: \[ 22 r^2 = 1408 \] Now, divide both sides by 22: \[ r^2 = \frac{1408}{22} \] Calculating this gives: \[ r^2 = 64 \] ### Step 3: Find the radius \(r\) Taking the square root of both sides, we find: \[ r = \sqrt{64} = 8 \, \text{cm} \] ### Step 4: Find the slant height \(l\) The slant height \(l\) of the cone can be found using the Pythagorean theorem: \[ l = \sqrt{h^2 + r^2} \] where \(h\) is the height of the cone (6 cm). Plugging in the values: \[ l = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 \, \text{cm} \] ### Step 5: Calculate the curved surface area The formula for the curved surface area (CSA) of a cone is: \[ \text{CSA} = \pi r l \] Substituting the known values: \[ \text{CSA} = \frac{22}{7} \times 8 \times 10 \] Calculating this gives: \[ \text{CSA} = \frac{1760}{7} \, \text{cm}^2 \] ### Final Answer Thus, the curved surface area of the cone is: \[ \frac{1760}{7} \, \text{cm}^2 \] ---
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