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What is the value of (0.2)^(2)+(0.02)^(2...

What is the value of `(0.2)^(2)+(0.02)^(2)+(0.002)^(2)` ?

A

2.404404

B

0.040404

C

0.00404

D

0.00044

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( (0.2)^2 + (0.02)^2 + (0.002)^2 \), we can follow these steps: ### Step 1: Calculate each term separately 1. **Calculate \( (0.2)^2 \)**: \[ (0.2)^2 = 0.2 \times 0.2 = 0.04 \] 2. **Calculate \( (0.02)^2 \)**: \[ (0.02)^2 = 0.02 \times 0.02 = 0.0004 \] 3. **Calculate \( (0.002)^2 \)**: \[ (0.002)^2 = 0.002 \times 0.002 = 0.000004 \] ### Step 2: Add the results together Now, we will add the results from Step 1: \[ 0.04 + 0.0004 + 0.000004 \] To add these, we can align them by their decimal points: \[ \begin{array}{r} 0.040000 \\ + 0.000400 \\ + 0.000004 \\ \hline 0.040404 \\ \end{array} \] ### Final Result Thus, the value of \( (0.2)^2 + (0.02)^2 + (0.002)^2 \) is: \[ \boxed{0.040404} \]
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