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How many positive factors of 132 are the...

How many positive factors of 132 are there?

A

10

B

12

C

9

D

11

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of positive factors of 132, we will follow these steps: ### Step 1: Prime Factorization of 132 First, we need to find the prime factorization of 132. We can do this by dividing 132 by the smallest prime numbers until we reach 1. - Divide 132 by 2 (the smallest prime number): \[ 132 \div 2 = 66 \] - Divide 66 by 2: \[ 66 \div 2 = 33 \] - Now, divide 33 by 3 (the next smallest prime number): \[ 33 \div 3 = 11 \] - Finally, 11 is a prime number, so we stop here. Thus, the prime factorization of 132 is: \[ 132 = 2^2 \times 3^1 \times 11^1 \] ### Step 2: Use the Formula to Find the Number of Factors To find the total number of positive factors of a number, we use the formula based on its prime factorization. If a number \( n \) can be expressed as: \[ n = p_1^{e_1} \times p_2^{e_2} \times p_3^{e_3} \ldots \] where \( p_1, p_2, p_3, \ldots \) are prime factors and \( e_1, e_2, e_3, \ldots \) are their respective powers, then the number of positive factors \( d(n) \) is given by: \[ d(n) = (e_1 + 1)(e_2 + 1)(e_3 + 1) \ldots \] ### Step 3: Apply the Formula From the prime factorization \( 132 = 2^2 \times 3^1 \times 11^1 \): - For \( 2^2 \), the exponent \( e_1 = 2 \), so \( e_1 + 1 = 2 + 1 = 3 \). - For \( 3^1 \), the exponent \( e_2 = 1 \), so \( e_2 + 1 = 1 + 1 = 2 \). - For \( 11^1 \), the exponent \( e_3 = 1 \), so \( e_3 + 1 = 1 + 1 = 2 \). Now, we can calculate the total number of positive factors: \[ d(132) = (2 + 1)(1 + 1)(1 + 1) = 3 \times 2 \times 2 \] ### Step 4: Calculate the Result Now we multiply these results together: \[ d(132) = 3 \times 2 \times 2 = 12 \] Thus, the number of positive factors of 132 is **12**. ---
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