The e.m.f. of the cell, `Cu(s)|Cu^(2+)(aq)"||"Ag^(+)(aq)|Ag(s)` is 0.46 V. The standard reduction potential of `Ag^(+)//Ag` is 0.80 V. The standard reduction potential of `Cu^(2+)|Cu` will be

Options

A. `-0.34` V
B. 1.26 V
C. `-1.26` V
D. 0.34 V

Answer

D

Explanation

`E_("cel")^(@)=E^(@)(Ag^(+)"|"Ag)-E^(@)(Cu^(2+)"|"Cu)`
`0.46=0.80-E^(@)(Cu^(2+)"|"Cu)`
or `E^(@)(Cu^(2+)"|"Cu)=0.80-0.46=0.36V`.