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The e.m.f. of the cell, Mg"|"Mg^(2+)(1M)...

The e.m.f. of the cell, `Mg"|"Mg^(2+)(1M)"||"Pb^(2+)(1M)"|"Pb` is `[E^(@)(Pb^(2+)"|"Pb)=-0.14V, E^(@)(Mg^(2+)"|"Mg)=-2.37V]`

A

`-2.51` V

B

`-2.23` V

C

2.23 V

D

2.51 V

Text Solution

Verified by Experts

The correct Answer is:
C
`E^(@)=E^(@)(Pb^(2+)"|"Pb)-E^(@)(Mg^(2+)"|"Mg)`
`=-0.14-(-2.37)=2.23V`
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