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How is cell potential (E("cell")^(@)) re...

How is cell potential `(E_("cell")^(@))` related to equilibrium constant `(K_(c))` for a cell reaction ?

A

`E_("cell")^(@)=(2.303 RT)/(nF)log. (1)/(K_(c))`

B

`E_("cell")^(@)= nRT log R_(c)`

C

`E_("cell")^(@)-log K_(c)=(2.303 RT)/(nF)`

D

`E_("cell")^(@)=(2.303RT)/(nF) log K_(c)`.

Text Solution

Verified by Experts

The correct Answer is:
D
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