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The amount of electricity required to de...

The amount of electricity required to deposit 0.9 g of aluminium when the electrode reaction is :
`Al^(3+) + 3e^(-) rarr Al`
(atomic mass of `Al=27`)

A

`9.65xx10^(3)C`

B

`1.93xx10^(4)C`

C

`9.65xx10^(4)C`

D

`4.34xx10^(5)C`

Text Solution

Verified by Experts

The correct Answer is:
A
`Al^(3+)+3e^(-) rarr Al`
27 g of Al require `= 3xx96500C`
0.9 g of Al requires `=(3xx96500C)/(27)`
`=9650C` or `9.65xx10^(3)C`
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