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The emf of a galvanic cell constituted w...

The emf of a galvanic cell constituted with the electrodes `Zn^(2+)"|"Zn(-0.76V)` and `Fe^(2+)"|"Fe(-0.41V)` is :

A

`-0.35` V

B

`+1.17` V

C

`+0.35` V

D

`-1.17` V

Text Solution

Verified by Experts

The correct Answer is:
C
`E_("cell")^(@)=E_("cathode")^(@)-E_("Anode")^(@)`
`=E_(Fe^(2+)"|"Fe)^(@)-E_(Zn^(2+)"|"Zn)^(@)`
`= -0.41-(-0.76)`
`= +0.35V`
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