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CH(3)-C-=CHunderset(1%HgSO(4))overset(40...

`CH_(3)-C-=CHunderset(1%HgSO_(4))overset(40%H_(2)SO_(4))toAoverset("Isomerisation")toCH_(3)-underset(O)underset(||)(C)-CH_(3)` Structure of 'A' and type of isomerism in the above reaction are respectively.

A

Prop -1- en -2- o1 metamerism

B

Prop -1- en -1-o1 , tautomerism

C

Prop - 2 - en -2-o1 , geometrical isomerism

D

Prop -1- en-2- o1 , tautomerism

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Verified by Experts

The correct Answer is:
D
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C_(2)H_(2)underset(H_(2)SO_(4))overset(HgSO_(4))toAoverset(O)toB B is :

CH_(3)C-=C CH_(3)underset((ii)H_(2) O //Zn)overset((i)X)(to)H_(3)C-underset(O)underset(||)(C)-underset(O)underset(||)(C)-CH_(3) In the above reaction X is

In the reaction : Xunderset(443 K)overset(H_(2)SO_(4))(to)Yoverset(HBr)(to)Zunderset(H_(2)O)overset(KOH)(to)CH_(3)underset(OH)underset(|)(C)HCH_(3) X is :

Ph - CH_(2) - underset(D) underset(|)(CH) - CH_(3) overset(Br_(2)//hv)(rarr) Product of the above reaction will be :

CH_(3) - CH_(2) - CH_(2) - CH_(3) underset(Delta)overset(AlCl_(3))(rarr) CH_(3) -underset(CH_(3))underset(|)(CH) - CH_(3) Above reaction is an example of :

The IUPAC name of CH_(3)-underset(CH_(3))underset("| ")"C "=CH-underset(O)underset(||)C -CH_(3) is

CH_(3)-C-=CHunderset("dil."H_(2)SO_(4))overset(HgSO_(4))to(A) CH_(3)-C-=CHunderset((2) H_(2)O_(2)//HO^(-))overset((1)BH_(3).THF)to(B) Product (A) and (B) is differentiated by :

CH_(3)underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-underset(CH_(3))underset(|)(CH)-OHoverset("Conc. "H_(2)SO_(4))(to)A major product is :

The IUPAC name for the compound : CH_(3)-underset(O)underset(||)(C)-CH_(2)-CH_(2)OH is

MODERN PUBLICATION-ALDEHYDES , KETONES AND CARBOXYLIC ACIDS-Multiple Choice Questions ( Level - II )
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