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Resistance of a conductivity cell filled...

Resistance of a conductivity cell filled with a solution of an electrolyte of concentration `0.1M ` is `100 Omega.` The conductivity of this solution is `1.29S m ^(-1).` Resistance of the same cell when filled with `0.2M` of the same solution is `520 Omega.` The molar conductivity of `0.2M` solution of the electrolyte will be

A

`1240xx 10 ^(-4) S m 6(2) mol ^(-1)`

B

`1. 24 xx 10 ^(-4) S m^(2) mol ^(-1)`

C

`12.4 xx 10 ^(-4) S m ^(2) mol ^(-1)`

D

`124 xx 10 ^(-4) S m ^(2) mol ^(-1)`

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The correct Answer is:
C
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Resistance of 0.2 M solution of an electrolyte is 50Omega . The specific conductance of the solution is 1.4 S m^(-1) . If resistance of the 0.5 M solution of the same electrolyte is 280 Omega . The molar conductivity of 0.5 M solution of the electrolyte in Sm^(2)"mol"^(-1) is

Resistance of 0.2 M solution of an electrolyte is 50Omega . The specific conductance of the solution is 1.3 S m^(-1) . If resistance of the 0.4 M solution of the same electrolyte is 260 Omega , its molar conductivity is :

Resistance of a conductivity cell filled with 0.02 M KCl solution is 520 Omega . Calculate the conductivity and molar conductivity of that solution. [Cell constant of the cell = 1.29 cm^(-1) ].

(a) Define the following terms: (i) Limiting molar conductivity (ii) Fuel cell. (b) Resistance of a conductivity cell filled with 0.1 mol L^-1 KCl solution is 100 Omega . IF the resistance of the same cell when filled with 0.02 mol L^-1 KCl solution is 520 Omega , calculate the conductivity and molar conductivity of 0.02 mol L^-1 KCl solution. The conductivity of 0.1 mol L^-1 KCl solution is 1.29 times 10^-2 Omega^-1 cm^-1 .

The resistance of a 0.01 N solution of an electrolyte AB at 328 K is 100 ohm. The specific conductance of the solution is (cell constant =1 cm^(-1) ) :

c) Resistance of a conductivity cell containing 0.1 M KCl solution is 100Omega . Cell constant of the cell is 1.29/cm. Calculate the conductivity of the solution at the same temperature.

The resistance of a conductivity cell filled with 0.1 M KCl solution is 100 Omega . If R of the same cell when filled with 0.02 M KCl solution is 520 Omega , calculate the conductivity and molar conductivity of 0.02 M KCl solution. The conductivity of 0.1 M KCl solution is 1.29 S m^(-1) .

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