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A particle of charge - 16 xx 10^(-18) C ...

A particle of charge `- 16 xx 10^(-18)` C moving with a velocity `10 ms^(-1)` along the x-axis enters a region where a magnetic field of magnitude B is along the y-axis and an electric field of magnitude `10^(4)` V/m is along negative z-axis . If the charged particle continues moving along x-axis , find magnitude of B .

A

`10^(6) Wb//m^(2)`

B

`10^(6) Wb//m^(2)`

C

`10^(-3) Wb//m^(2)`

D

`10^(3) Wb//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`v = (E)/(B) :. B = (E)/(v) = (10^(4))/(10) = 10^(3) Wb//m^(2)`
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