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A particle of charge e and mass m moves ...

A particle of charge e and mass m moves with a velocity v in a magnetic field B applied perpendicular to the motion of the particle .The radius r of its path in the field is :

A

`(mu)/(Be)`

B

`(Be)/(mv)`

C

`(ev)/(Bm)`

D

`(Bv)/(em)`

Text Solution

Verified by Experts

The correct Answer is:
A
Radius of path , r ` = (mv)/(qB)`
Here, q = e
So, ` r = (mv)/(eB)`
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