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A proton beam enters a magnetic field of...

A proton beam enters a magnetic field of `10^(-4) Wb m^(-2)` normally. If the specific charge of the proton is `10^(11) C Kg^(-1)` and its velocity is `10^(9) ms^(-1)` , then radius of the circle described will be

A

10 m

B

1 m

C

0 . 1m

D

100 m

Text Solution

Verified by Experts

The correct Answer is:
D

`r = (mv)/(qB) = (10^(9))/(((q)/(m))(10^(-4)))`
`r = (10^(9))/( 10^(11) xx 10^(-4)) = 100 m`
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