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If a, b, c are real and a!=b, then the r...

If `a, b, c` are real and `a!=b`, then the roots of the equation, `2(a-b)x^2-11(a + b + c) x-3(a-b) = 0` are :

A

real and equal

B

real and unequal

C

purely imaginary

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
We have
`2(a-b)x^(2)-11(a+b+c)x-3(a-b)=0`
`:.D={-11(a+b+c)}^(2)-4.29a-b).(-3)(a-b)`
`=121(a+b+c)^(2)+24(a-b)^(2)gt0`
Therefore the roots are real and unequal.
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