Find the number of permutations that can be had from the letters of the word 'OMEGA' (i) O and A occuping end places. (ii) E being always in the middle.

Explanation

(i) When O and A occuping end places.
i.e., M E G (OA)
the first three letters (M,E,G) can be arranged themselves by 3!=6 ways and last two letters (O,A) can be arranged themselves by 2!=2 ways.
`therefore`Total number of such words
`=6xx2=12` ways
(ii) When E is the fixed in the middle, then there are four places left to be filled by four remaining letters O,M, G and A and this can be done in 4! ways.
`therefore` Total number of such words=4!=24 ways.