Home
Class 12
MATHS
The number of proper divisors of 2^(p)*6...

The number of proper divisors of `2^(p)*6^(q)*21^(r),AA p,q,r in N`, is

A

(a) (p+q+1)(q+r+1)(r+1)

B

(b) (p+q+1)(q+r+1)(r+1)-2

C

(c) (p+q)(q+r)r-2

D

(d) (p+q)(q+r)r

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

The number of odd proper divisors of 3^(p)*6^(q)*15^(r),AA p,q,r, in N , is

Number of odd proper divisors of 3^(p).6^(m).21^(n) is :

Statement-1: The number of divisors of 10! Is 280. Statement-2: 10!= 2^(p)*3^(q)*5^(r)*7^(s) , where p,q,r,s in N.

Given that the divisors of n=3^(p)*5^(q)*7^(r) are of of the form 4lamda+1,lamdage0 . Then,

The negation of p to (q ^^ r) is

The inverse of the proposition (p ^^ ~q) to r is

The inverse of the proposition (p ^^ ~q) rarr r is

The simplified form of (p^^q)vv(p^^r)=

The negation of p ^^(q rarr ~r) is

The negation of (p to q) ∨ (p to r) is