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The exponent of 7 in 100C50 is...

The exponent of 7 in `100C_50` is

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The correct Answer is:
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`because .^(100)C_(50)=(100!)/((50!)^(2))`
`thereforeE_(7)(100!)=[100/7]+[100/7^(2)]=14+2=16`
and `E_(7)(50!)=[50/7]+[50/7^(2)]=7+1=8`
`thereforeE_(7)` in `(.^(100)C_(50))=16-2xx8=0`
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