Home
Class 12
MATHS
Statement-1: The smallest positive integ...

Statement-1: The smallest positive integer n such that n! can be expressed as a product of n-3 consecutive integers, is 6.
Statement-2: Product of three consecutive integers is divisible by 6.

A

Statement-1 is true, statement-2 is true, statement-2 is a correct explanation for statement-1

B

Statement-1 is true, statement-2 is true, statement-2 is not a correct explanation for statement-1

C

Statement-1 is true, statement-2 is false

D

Statement-1 is false, statement-2 is true

Text Solution

Verified by Experts

The correct Answer is:
B

Statement-1 is true
`therefore6!=720=8xx9xx10` i.e., product off 6-3=3 consecutive integers and statement-2 is also true, but statement-2 is not a correct explanation for statement-1.
Promotional Banner

Similar Questions

Explore conceptually related problems

Prove that the product of three consecutive positive integers is divisible by 6.

Prove that the sum of three consecutive even numbers is divisible by 6.

Prove that the product of any two consecutive positive integers is divisible by 2.

Find the sum of the first 40 positive integers divisible by 6.

Find the sum of the first 40 positive integers divisible by 6.

Find the sum of the first 40 positive integers divisible by 6.

Find the sum ofthe first 40 positive integers divisible by 6.

The smallest integer n such that ((1 + i)/(1-i))^(n) = 1 is

If the product of two consecutive integers is 306, write its quadratic representation.

Find the least positive integer 'n' such that ((1+i)/(1-i))^(n) =1 .