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Let A={(x,y : y=e^x , x in R} , B={(x,y)...

Let A={(x,y : `y=e^x , x in R`} , B={(x,y): y=x, x `in` R} . Then :

A

`B sub A`

B

`A sub B`

C

`A nn B = phi`

D

`A uu B`

Text Solution

Verified by Experts

The correct Answer is:
B

`A = {(x,y):y=e^(x),x inR}`
`B = {(x, y):y=x,x inR}`

`therefore A sub B`
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