If function f:AtoB is a bijective , then...

If function `f:AtoB` is a bijective , then `f^(-1)` of is

A

`fof^(-1)`

B

`f`

C

`f^(-1)`

D

`I_(A)` (the identity map of the set A)

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The correct Answer is:

D

`f : A rarr B`
f is a function, then `f^(-1)` is also a bijective function. Composite function `(f^(-1) of) = I_(A)`

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